Hybridization Of So42 __hot__

The sp3 hybridization in SO42- results in a tetrahedral electron geometry. However, the actual molecular shape is not tetrahedral due to the presence of lone pairs on the oxygen atoms and the delocalization of electrons in the sulfate ion.

To form the sulfate ion, sulfur is bonded to four oxygen atoms. The sulfur atom shares its four valence electrons with four oxygen atoms, forming four equivalent σ bonds. hybridization of so42

= number of atoms bonded to central atom + number of lone pairs on central atom. The sp3 hybridization in SO42- results in a

The electronic configuration of sulfur is [Ne] 3s2 3p4. hybridization of so42